French Open · R128 · Clay · best of 3 · May 25, 2026, 7:40 PM UTC

Camila Osorio vs. Ekaterina Alexandrova — result and pick review

By The Maiden Desk · May 25, 2026

Every pick below gets graded after the match — wins and misses both stay up.

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Result

✗ Pick wrong

Camila Osorio won 6-2 6-4 · May 25, 2026, 9:15 PM UTC

A miss: Ekaterina Alexandrova at 67% lost to Camila Osorio (6-2 6-4). It counts against our record like every other miss.

Monday's French Open first round pits Camila Osorio against Ekaterina Alexandrova on clay. Ekaterina Alexandrova has dropped 2 straight and sits at 2-8 over the last ten. Camila Osorio is 6-4 across recent matches.

Camila Osorio has had the better of this rivalry, winning 3 of 3 against Ekaterina Alexandrova. On clay specifically it reads 1-0 Osorio — worth more than the overall number this week.

The serve is where this match separates: Alexandrova has been winning 66.7% of first-serve points to Osorio's 61.4%, and on clay that gap compounds fast. Expect resistance, but the match-level math tilts clearly toward Alexandrova.

The numbers behind the pick

Surface ratings

Clay rating

Camila Osorio

1712

Ekaterina Alexandrova

1681

Overall rating

Camila Osorio

1741

Ekaterina Alexandrova

1792

Serve

Serve (last 52 weeks)	Camila Osorio	Ekaterina Alexandrova
1st serve in	66.2%	58.8%
1st serve points won	61.4%	66.7%
2nd serve points won	43.3%	42.7%

Form

Camila Osorio

6–4

Ekaterina Alexandrova

2–8

Head to head

Camila Osorio leads the head-to-head 3-0. On clay: 1-0 Camila Osorio.

Full Osorio vs Alexandrova history →

Frequently asked questions

Who won Camila Osorio vs Ekaterina Alexandrova at French Open?: Camila Osorio won 6-2 6-4.
Was the Camila Osorio vs Ekaterina Alexandrova prediction correct?: A miss: Ekaterina Alexandrova at 67% lost to Camila Osorio (6-2 6-4). It counts against our record like every other miss.
What is the head-to-head record between Camila Osorio and Ekaterina Alexandrova?: Camila Osorio leads the head-to-head 3-0. On clay: 1-0 Camila Osorio.